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In today's Gazette, Coach Ford hints that our only hope of "winning" the league would be for Sacred Heart to beat Monmouth and for all three teams to wind up 6-1. Does anyone know how the league representative in the ECAC bowl would be determined under those circumstances? If Sacred Heart beats Monmouth, but loses to someone else, and only Albany and Monmouth wound up 6-1, Monmouth would win based on head to head.

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Looking at this objectively, if you have three teams tie for first place, with one loss apiece, you have to think that the first tiebreaker, head-to-head, obviously doesn't apply, because Sacred Heart beats (in theory) Monmouth, Monmouth beats Albany, Albany beats Sacred Heart.


I would have ASSUMED (couldn't find it on NEC website) that the next tiebreaker would be conference record. However, that doesn't make sense, since in order to have tie, obviously this aspect is tied as well (unless for some reason the teams didn't play the same number of conference games).


So, then possible other tiebreakers COULD be: overall record, record vs. common opponents (both conference and non-conference), strength of schedule, point differential (scored vs. allowed), point differential in conference games only, point differential in games vs. other tied opponents only (Monmouth and Sacred Heart).


Or, if you reference this page:

<A HREF="http://www.northeastconference.org/mfootball.html"> 1998 NEC Standings</A>, you will see they went with a co-champion that year. However, that would not help determine who would rep. the conference in the ECAC game.

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